3m^2-2m-11=0

Solution for 3m^2-2m-11=0 equation:

3m^2-2m-11=0

a = 3; b = -2; c = -11;
Δ = b2-4ac
Δ = -22-4·3·(-11)
Δ = 136
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{136}=\sqrt{4*34}=\sqrt{4}*\sqrt{34}=2\sqrt{34}$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-2\sqrt{34}}{2*3}=\frac{2-2\sqrt{34}}{6}
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+2\sqrt{34}}{2*3}=\frac{2+2\sqrt{34}}{6}
$